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Student’s Name Instructor’s name Course Date STAT100 Trimester 3 2016 Assignment 2 Question 1 Binomial distribution conditions that are satisfied for X 1. For each of the n trials there is only two possible outcomes. In this case every time a baby is born there are only two possible outcomes in terms of gender. It’s either the child is male or female. 2. Each trial has the same probability of success. In this case each time a baby is born which is the trial in our case it has a probability of 0.49 of being female and 0.51 of being male. 3. Each trial is independent. shows that 89.43% of the children had MDI of at least 80. b). MDI score that is the 99th percentile. P (x-10016) = 0.99 Find the z score for probability 0.99 which is 2. 3263.Therefore; x-10016=2.3263 X=100+(16*2.3263) =132.22 (ii) MDI score such that only 1% of the population has MDI below it means that its cumulative probability must be equal to 0.01. Therefore P (x-10016 )=0.01 The z value for the 0.01 probability is -2.3263 therefore x-10016=-2.3263X=100+(16*-2.3263) =62.78 c)Z score corresponding to the lower quartile of the above distributions probability of lower quartile is 0.25 to find the z score of 0.25 NORMSINV (0.25) = -0.6745 [...]
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I have attached a zip file containing three chapters (7-9) and a file called studybook and You can have a look on chapters 7-9 in case it helps. The assignment covers covers chapters 7-9 from the book. Most of the material is in hard copy of book but I just attached these files in case it might be helpful. Thankschapters 7-9 from the
Subject Area: Statistics
Document Type: Dissertation Proposal
