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Question 1 {(1 4) (4 1) (2 1) (0 0)} Domain (x) Range(y) 23812576835.1420 4110The set of the ordered pairs is a function because each x value is assigned to only one y value. Question 2: The standard form for the line going through the points (-1 4) and (2 2). Using the formula: y - y1 = y2-y1x2-x1 * (x - x1) In this case: x1 = -1 y1 = 4 x2 = 2 y2 = 2. So y - y1 = y2-y1x2-x1 * (x - x1) y - 4= 2 - 42 -(-1) * (x – (-1)) y - 4= - 23 * (x + 1) y - 4= - 23 x - 23Multiply all both sides by 3 Y*3 – 4*3= - 23 x *(3) - 23 *3 To become 3y – 12 = -2x -2 Add 2x on both sides 3y – 12 + 2x h (2.5) = 196 Therefore the maximum height is 196 feet. b). h (t) = -16t2 + 80t + 96 When the ball lands on the ground the height = 0 Therefore when the ball hits the ground; -16t2 + 80t + 96 = 0 Dividing all through by 8 to simplify the equation -16t28 + 80t8 + 968 = 08It becomes -2t2 + 10t + 12 =0 Factors of ac that add up to b Factors of -2*12=-24 that add up to 10 The factors are 12 and -2 Hence the expression becomes -2t2 -2t + 12t + 12 =0 -2t (t + 1) + 12 (t+1) = 0 Factoring out the common factor t+1 (t+1) (-2t + 12) =0 t + 1=0 t=-1 time cannot be negative -2t + 12 =0 -2t = -12 t = 6 Therefore the ball lands on the ground after 6 seconds. [...]
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Please see instructions on attached file. Basically, the assignment requires solving math problems. Directions must be followed exactly and work/solution shown.
Subject Area: Mathematics
Document Type: Dissertation Proposal
